How do you simplify #(6^-2x^3y^-4)/(2^-4x^3y^-4)#?

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Answer 1 · 2018-05-25T21:41:17

#4/9#

The #x# and #y# terms have the same exponent on the top and bottom, so they will essentially cancel each other out. We're left with

#6^-2/2^-4#

We can rewrite this as being equal to

#(1/6^2)/(1/2^4)#

Which can be further simplified as follows

#=>(1/36)/(1/16)#

#=>1/36*16#

#=>16/36#

#=>4/9#

Hope this helps!