How do you simplify #6 + 3[(12 / 4) + 5] # using PEMDAS?

1 Answer
P dilip_k
May 13, 2016

#=30 #

Explanation:

Division operation within 1st bracket(or Parentheses ) is done first
#6 + 3[(cancel12^3 / cancel4) + 5] #
#=6 + 3[3 + 5] #
Now operation on third bracket( Parentheses ) gives
#=6 + 3*8 #
Now operation of multiplication comes,it gives
#=6 + 24 #
Then operation of addition gives the result
#=30 #
#PEMDAS->#"Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction". Rule is thus followed in order

Related questions
See all questions in PEMDAS
Impact of this question
1428 views around the world
You can reuse this answer
Creative Commons License