How do you simplify $6^{3} - 3 \times (3^{2} \times 2) + 5$ $6^3 - 3 times (3^2 times 2) + 5$ using order of operations?

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How do you simplify $6^{3} - 3 \times (3^{2} \times 2) + 5$ $6^3 - 3 times (3^2 times 2) + 5$ using order of operations?

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Answer 1 · 2015-11-14T08:44:20

We can use the BODMAS rule to solve this.

$167$ $167$

Explanation:

The order of operations is given by the BODMAS rule. B=Brackets; O=Of; D=Division; M=Multiplication; A=Addition; S=Subtraction. B i.e. brackets have highest priority and the priority decreases till S i.e. subtraction.

$6^{3} - 3 \cdot (3^{2} \cdot 2) + 5$ $6^3-3*(3^2*2)+5$

= $6 \cdot 6 \cdot 6 - 3 \cdot (9 \cdot 2) + 5)$ $6*6*6-3*(9*2)+5)$

= $216 - 3 \cdot (18) + 5$ $216-3*(18)+5$

= $216 - 54 + 5$ $216-54+5$

= $216 + 5 - 54$ $216+5-54$

= $221 - 54$ $221-54$

= $167$ $167$

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How do you simplify $6^{3} - 3 \times (3^{2} \times 2) + 5$ $6^3 - 3 times (3^2 times 2) + 5$ using order of operations?

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Explanation:

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