How do you simplify ${(6^{3} \cdot 6^{- 2})}^{- 2}$ $(6^3*6^-2)^-2$ ?

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Answer 1 · 2015-05-25T19:29:52

Three important exponential rules here:

So, following the first:

${(6^{3 - 2})}^{- 2} = {(6^{1})}^{- 2}$ $(6^(3-2))^-2=(6^1)^-2$

Follolwing the second:

$6^{1 \cdot (- 2)} = 6^{- 2}$ $6^(1*(-2))=6^-2$

And, finally:

$6^{- 2} = \frac{1}{6^{2}} = \frac{1}{36}$ $6^-2=1/6^2=1/36$

How do you simplify (63⋅6−2)−2(6^3*6^-2)^-2?