How do you simplify #6+4 (3-1)^2 ÷ sqrt25# using PEMDAS?

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Answer 1 · 2016-02-26T02:04:34

First, it is parenthesis, so we do #3-1 = 2 # first inside the parenthesis

Next is exponents, so we get #2^2 = 4#

Now our equation looks like #6 + 4*4 / sqrt25#

We can get the square root out because #sqrt25 = 5#

So we have #6 + 4*4 / 5#

MD are together, so we multiply and divide

#6 + 16 / 5#

#6 + 3.2#

Then we add them

#9.2#

And we are done.