How do you simplify $6+4 (3-1)^2 ÷ sqrt25$ using PEMDAS?

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Answer 1 · 2016-02-26T02:04:34

First, it is parenthesis, so we do $3-1 = 2$ first inside the parenthesis

Next is exponents, so we get $2^2 = 4$

Now our equation looks like $6 + 4*4 / sqrt25$

We can get the square root out because $sqrt25 = 5$

So we have $6 + 4*4 / 5$

MD are together, so we multiply and divide

$6 + 16 / 5$

$6 + 3.2$

Then we add them

$9.2$

And we are done.

How do you simplify 6+4 (3-1)^2 ÷ sqrt256+4 (3-1)^2 ÷ sqrt25 using PEMDAS?