How do you simplify $[(6+7) + 3²] times (4÷ 8)$ using PEMDAS?

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Answer 1 · 2016-02-25T16:55:08

$11$

Order of operations - always do brackets first, then multiply and divide, then add and subtract.

$therefore[(6+7)+3^2]xx(4-:8) = (13+9) xx 1/2$

$=22 xx 1/2$

$=11$

How do you simplify [(6+7) + 3²] times (4÷ 8) [(6+7) + 3²] times (4÷ 8) using PEMDAS?