How do you simplify #6[n+(n-d)]-3[n-(n-d)]#? Algebra Properties of Real Numbers When to Use the Distributive Property 1 Answer G_Ozdilek Apr 19, 2018 By arranging the equation Explanation: #6[n+(n-d)] - 3[n-(n-d)]# #=6n + 6n -6d - 3n +3n +3d# #=12n - 6d +3d# #=12n - 3d# #=3(4n-d)# Your answer is #3(4n-d)# Answer link Related questions How do you simplify #(9-6y)/3#? How do you simplify #\frac{10x+8y-1}{2# using the distributive property? How do you use the distributive property to simplify #- \frac{6z - 2}{3}#? How do you simplify #6 + (x - 5) + 7#? How do you use the distributive property to simplify #(r + 3)(-5)#? What is the student error if a student rewrote #4(9x + 10)# as #36x + 10# ? How do you use the distributive property to calculate #6(19.99)# in your head? When do you use the Distributive Property? How do you use the distributive property to multiply #6(3r+4s)#? How do you use the distributive property to simplify #79(101)#? See all questions in When to Use the Distributive Property Impact of this question 1358 views around the world You can reuse this answer Creative Commons License