How do you simplify $6 x \cdot (\frac{1}{x^{- 3}})$ $6x*(1/x^-3)$ ?

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Answer 1 · 2016-12-13T15:47:12

$6 x^{4}$ $6x^4$

Use the fact that

$x^{- 3} = \frac{1}{x^{3}}$ $x^(-3) = 1/x^3$

to write

$\frac{1}{x^{- 3}} = \frac{1}{\frac{1}{x^{3}}} = 1 \cdot x^{3} = x^{3}$ $1/x^(-3) = 1/(1/x^3) = 1 * x^3 = x^3$

You now have

$6 x \cdot x^{3} = 6 x^{4}$ $6x * x^3 = 6x^4$

How do you simplify 6x⋅(1x−3)6x*(1/x^-3)?