How do you simplify # (6y – 2) + (7y + 3) – (2y – 6)#?

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Answer 1 · 2016-06-12T23:00:51

#11y+7#

First We have to expand :
#(6y-2) + (7y+3) -(2y-6)#

=#6y -2 + 7y +3 -2y +6#

Now adding the same unknowns we have:

#6y - 2 + 7y +3 - 2y + 6#

=#6y +7y -2y -2 +3 +6#

=#11y +7#