How do you simplify $7 r s (4 r^{2} + 9 s^{3} - 7 r s)$ $7rs(4r^2+9s^3-7rs)$ ?

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How do you simplify $7 r s (4 r^{2} + 9 s^{3} - 7 r s)$ $7rs(4r^2+9s^3-7rs)$ ?

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Answer 1 · 2016-10-31T10:29:03

$28 r^{3} s + 63 r s^{4} - 49 r^{2} s^{2}$ $28r^3s+63rs^4-49r^2s^2$

Explanation:

Distribute the bracket by multiplying each term in the bracket by 7rs.

$\Rightarrow 7 r s (4 r^{2} + 9 s^{3} - 7 r s)$ $rArrcolor(red)(7rs)(4r^2+9s^3-7rs)$

$= (7 r s \times 4 r^{2}) + (7 r s \times 9 s^{3}) + (7 r s \times (- 7 r s))$ $=(color(red)(7rs)xx4r^2)+(color(red)(7rs)xx9s^3)+(color(red)(7rs)xx(-7rs))$

$= 28 r^{3} s + 63 r s^{4} - 49 r^{2} s^{2}$ $=28r^3s+63rs^4-49r^2s^2$

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How do you simplify $7 r s (4 r^{2} + 9 s^{3} - 7 r s)$ $7rs(4r^2+9s^3-7rs)$ ?

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How do you simplify 7rs(4r2+9s3−7rs)7rs(4r^2+9s^3-7rs)?

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How do you simplify $7 r s (4 r^{2} + 9 s^{3} - 7 r s)$ $7rs(4r^2+9s^3-7rs)$ ?