How do you simplify $7 x y (x^{2} + y) - 11 x y^{2} (x^{2} - 1)$ $7xy (x^2 + y) - 11 xy^2 (x^2 -1)$ ?

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How do you simplify $7 x y (x^{2} + y) - 11 x y^{2} (x^{2} - 1)$ $7xy (x^2 + y) - 11 xy^2 (x^2 -1)$ ?

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Answer 1 · 2015-07-16T09:06:30

$7 x^{3} y - 11 x^{3} y^{2} + 18 x y^{2} = x y (7 x^{2} y - 11 x^{2} y + 18 y^{2})$ $7x^3y-11x^3y^2+18xy^2=xy(7x^2y-11x^2y+18y^2)$

Explanation:

First, distribute the outer terms into the brackets:

$7 x y (x^{2} + y) - 11 x y^{2} (x^{2} - 1)$ $7xy(x^2+y)-11xy^2(x^2-1)$
= $(7 x y \cdot x^{2} + 7 x y \cdot y) + (- 11 x y^{2} \cdot x^{2} + 11 x y^{2})$ $(7xy*x^2+7xy*y)+(-11xy^2*x^2+11xy^2)$

Simplify using exponent rules

$= 7 x^{3} y + 7 x y^{2} - 11 x^{3} y^{2} + 11 x y^{2}$ $=7x^3y+7xy^2-11x^3y^2+11xy^2$

Add like terms

$= 7 x^{3} y - 11 x^{3} y^{2} + 18 x y^{2}$ $=7x^3y-11x^3y^2+18xy^2$

If you want, you can factor out an $x y$ $xy$ to simplify further

$= x y (7 x^{2} y - 11 x^{2} y + 18 y^{2})$ $=xy(7x^2y-11x^2y+18y^2)$

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How do you simplify $7 x y (x^{2} + y) - 11 x y^{2} (x^{2} - 1)$ $7xy (x^2 + y) - 11 xy^2 (x^2 -1)$ ?

1 Answer

Explanation:

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How do you simplify 7xy(x2+y)−11xy2(x2−1)7xy (x^2 + y) - 11 xy^2 (x^2 -1)?

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Explanation:

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How do you simplify $7 x y (x^{2} + y) - 11 x y^{2} (x^{2} - 1)$ $7xy (x^2 + y) - 11 xy^2 (x^2 -1)$ ?