Count the number of terms in the expression.
color(blue)([(8+5) (6-2) ^2])color(red)( - (4times17 div2))" "larr[(8+5)(6−2)2]−(4×17÷2) ← there are 2 terms
Simplify each term to a single answer which will be added or subtracted in the last step.
In each term the order to follow is:
Brackets first - work from the innermost bracket
Multiply and divide
" "color(blue)([(8+5) (6-2) ^2])color(red)( - (4times17 div2)) [(8+5)(6−2)2]−(4×17÷2)
color(white)(wxxw)darrcolor(white)(wxw)darrcolor(white)(wxxxw)darrw×w↓wxw↓w×xw↓
=color(blue)([(13) xx" " (4) ^2])" "color(red)( - (68 div2))=[(13)× (4)2] −(68÷2)
color(white)(wxxw)darrcolor(white)(wxw)darrcolor(white)(wxxxw)darrw×w↓wxw↓w×xw↓
=color(blue)([(13)""xx" " (16)])" "color(red)( - (34))=[(13)× (16)] −(34)
color(white)(wxxxxw)darrw××w↓
=color(white)(xxxx)color(blue)(208)color(white)(xxxx)color(red)( - 34)=××208××−34
=174=174
