How do you simplify #(8 times b) times 4 #?

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Answer 1 · 2018-03-12T22:37:17

Distribute the 4 to the term inside the parentheses to get #32b#

First, lets rewrite the equation slightly:

#4*(8b)#

Expanding this, you could distribute the 4 as such:

#4*(8b)=8b+8b+8b+8b=32b#

OR you could just multiply the numeric coefficients together:

#(4*8)b=32b#