How do you simplify $8 \div 4 + 1 (6 - 4) + 4 \div 2 - 6$ $8div4+1(6-4)+4div2-6$ ?

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Answer 1 · 2016-08-03T09:23:12

$0$ $0$

Count the number of terms first. In this case there are 4 terms.

You can simplify within each term until there is a single answer for each term. Do more than one simplification in a line. This saves time and space.

Addition and subtraction are done in the LAST step.

$8 \div 4 + 1 (6 - 4) + 4 \div 2 - 6$ $color(red)(8div4)color(blue)(+1(6-4))color(magenta)(+4div2)color(green)(-6)$

= $2 + 1 \times 2 + 2 - 6$ $color(red)(2)color(blue)(+1xx2)color(magenta)(+2)color(green)(-6)$

= $2 + 2 + 2 - 6$ $color(red)(2)color(blue)(+2)color(magenta)(+2)color(green)(-6)$

= $0$ $0$

How do you simplify 8÷4+1(6−4)+4÷2−68div4+1(6-4)+4div2-6?