How do you simplify 8sqrt(11b^4) - sqrt(99b^4)811b499b4?

1 Answer
May 18, 2015

By exponential definition, we know that root(n)(a^m)=a^(m/n)nam=amn

In this case, we can do the same for bb, factoring it out:

8b^2sqrt(11)-b^2sqrt(99)8b211b299
However, we can see that 99=11*999=119, so

8b^2sqrt(11)-b^2sqrt(11*9)8b211b2119

However, 99 is a square number. Thus, we can take its root out of the square root.

8b^2sqrt(11)-3b^2sqrt(11)8b2113b211

However, as both factors are multiplying b^2sqrt(11)b211, we can factor it in function of such elements:

b^2sqrt(11)(8-3)b211(83)