How do you simplify $8 y^{2} + 7 y + 4 - 3 (2 y^{2} - 5 y - 8)$ $8y^ { 2} + 7y + 4- 3( 2y ^ { 2} - 5y - 8)$ ?

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How do you simplify $8 y^{2} + 7 y + 4 - 3 (2 y^{2} - 5 y - 8)$ $8y^ { 2} + 7y + 4- 3( 2y ^ { 2} - 5y - 8)$ ?

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Answer 1 · 2017-10-24T06:07:15

$2 (y^{2} + 11 y + 14)$ $2(y^2+11y+14)$

Explanation:

Given -

$8 y^{2} + 7 y + 4 - 3 (2 y^{2} - 5 y - 8)$ $8y^2+7y+4-3(2y^2-5y-8)$

$8 y^{2} + 7 y + 4 - 6 y^{2} + 15 y + 24$ $8y^2+7y+4-6y^2+15y+24$

$2 y^{2} + 22 y + 28$ $2y^2+22y+28$
$2 (y^{2} + 11 y + 14)$ $2(y^2+11y+14)$

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How do you simplify $8 y^{2} + 7 y + 4 - 3 (2 y^{2} - 5 y - 8)$ $8y^ { 2} + 7y + 4- 3( 2y ^ { 2} - 5y - 8)$ ?

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How do you simplify 8y^ { 2} + 7y + 4- 3( 2y ^ { 2} - 5y - 8)8y2+7y+4−3(2y2−5y−8)8y^ { 2} + 7y + 4- 3( 2y ^ { 2} - 5y - 8)?

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How do you simplify $8 y^{2} + 7 y + 4 - 3 (2 y^{2} - 5 y - 8)$ $8y^ { 2} + 7y + 4- 3( 2y ^ { 2} - 5y - 8)$ ?