How do you simplify #(9/16)^(-1/2)#?

1 Answer
Apr 23, 2018

#4/3#

Explanation:

As the power holds a negative, this means that we can put 1 over #9/16#, which is equal to #16/9# leaving us with;

#(16/9)^(1/2)#

The power of #1/2# is also another way of writing the square root;

= #sqrt (16/9)#

From here you can find the square roots of 16 and 9, and giving you your final answer;

= #4/3#