How do you simplify $9 m (m + n + 1) - 8 (m^{2} + m - n)$ $9m (m + n + 1) - 8 (m^2 + m - n)$ ?

Question

How do you simplify $9 m (m + n + 1) - 8 (m^{2} + m - n)$ $9m (m + n + 1) - 8 (m^2 + m - n)$ ?

1 Answer

Impact of this question

2379 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-11T21:26:51

I found: $m^{2} + m + 8 n + 9 m n$ $m^2+m+8n+9mn$

Explanation:

You can multiply and get rid of the brackets:
$= 9 m^{2} + 9 m n + 9 m - 8 m^{2} - 8 m + 8 n =$ $=9m^2+9mn+9m-8m^2-8m+8n=$
add together similar terms:
$= m^{2} + m + 8 n + 9 m n$ $=m^2+m+8n+9mn$

Science

Math

Humanities

... and beyond

How do you simplify $9 m (m + n + 1) - 8 (m^{2} + m - n)$ $9m (m + n + 1) - 8 (m^2 + m - n)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify 9m (m + n + 1) - 8 (m^2 + m - n)9m(m+n+1)−8(m2+m−n)9m (m + n + 1) - 8 (m^2 + m - n)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you simplify $9 m (m + n + 1) - 8 (m^{2} + m - n)$ $9m (m + n + 1) - 8 (m^2 + m - n)$ ?