How do you simplify $a^{5} \cdot a^{- 9} \cdot a^{3}$ $a^5a^-9a^3$ ?

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Answer 1 · 2018-05-29T13:51:15

$a^{- 1}$ $a^-1$

Given: $a^{5} \cdot a^{- 9} \cdot a^{3}$ $a^5*a^-9*a^3$

Use the algebraic property which states that $a^{b} \cdot a^{c} \cdot a^{d} = a^{b + c + d}$ $a^b*a^c*a^d=a^(b+c+d)$ .

So here we have:

$= a^{5 + (- 9) + 3}$ $=a^(5+(-9)+3)$

$= a^{- 4 + 3}$ $=a^(-4+3)$

$= a^{- 1}$ $=a^-1$

How do you simplify a^5*a^-9*a^3a5⋅a−9⋅a3a^5*a^-9*a^3?