How do you simplify #abs(-14)#?
1 Answer
Dec 22, 2015
Explanation:
If
#abs(x) = { (x, if x >= 0), (-x, if x < 0) :}#
In our case
If
#abs(z) = sqrt(z bar(z))#
where
For example:
#abs(3+4i) = sqrt((3+4i)(3-4i)) = sqrt(3^2+4^2) = sqrt(9+16)#
#= sqrt(25) = 5#
This gives the same value as the above definition for Real numbers, if