How do you simplify #abs(2+3i)#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Sridhar V. May 7, 2018 #" "# #color(red)(|2+3i|=sqrt(13)# Explanation: #" "# Given: #color(blue)(|2+3i|# #color(brown)(|a+bi|=sqrt(a^2+b^2)# So, #|2+3i| =sqrt(2^2+3^2# #rArr sqrt(4+9)# #rArr sqrt(13)# Hence, #color(blue)(|2+3i|=sqrt(13)# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1293 views around the world You can reuse this answer Creative Commons License