How do you simplify #abs(20 + 21i )#?
1 Answer
Dec 6, 2015
Explanation:
Using Pythagoras Theorem,
#abs(a+bi) = sqrt(a^2+b^2)#
So in our case:
#abs(20+21i) = sqrt(20^2+21^2) = sqrt(400+441) = sqrt(841) = 29#
