How do you simplify and divide $(12 y^{2} + 36 y + 15) \div (6 y + 3)$ $(12y^2+36y+15)div(6y+3)$ ?

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Answer 1 · 2016-12-17T12:10:44

The answer is $= 2 y + 5$ $=2y+5$

Let's do some simplification, some factorisation

$(12y^2+36y+15)/(6y+3)=(cancel3(4y^2+12y+5))/(cancel3(2y+1))$

$=(cancel(2y+1)(2y+5))/cancel(2y+1)$

$=2y+5$

How do you simplify and divide (12y^2+36y+15)div(6y+3)(12y2+36y+15)÷(6y+3)(12y^2+36y+15)div(6y+3)?