How do you simplify and divide $(28c^3d-42cd^2+56cd^3)div(14cd)$ ?

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Answer 1 · 2016-10-04T21:02:04

$2c^2-3d+4d^2$

$(28c^3d-42cd^2+56cd^3)/(14cd)$

There are 2 methods:

$1. rarr$ factor the numerator and cancel

$(cancel(14cd)(2c^2-3d+4d^2))/cancel(14cd)$

= $2c^2-3d+4d^2$

$2. rarr$ make 3 separate fractions and simplify each

= $(28c^3d)/(14cd) -(42cd^2)/(14cd) +(56cd^3)/(14cd)$

= $2c^2-3d+4d^2$

How do you simplify and divide (28c^3d-42cd^2+56cd^3)div(14cd)(28c^3d-42cd^2+56cd^3)div(14cd)?