How do you simplify and divide #(28c^3d-42cd^2+56cd^3)div(14cd)#? Precalculus Real Zeros of Polynomials Long Division of Polynomials 1 Answer EZ as pi Oct 4, 2016 #2c^2-3d+4d^2# Explanation: #(28c^3d-42cd^2+56cd^3)/(14cd)# There are 2 methods: #1. rarr# factor the numerator and cancel #(cancel(14cd)(2c^2-3d+4d^2))/cancel(14cd)# =#2c^2-3d+4d^2# #2. rarr# make 3 separate fractions and simplify each =#(28c^3d)/(14cd) -(42cd^2)/(14cd) +(56cd^3)/(14cd)# =#2c^2-3d+4d^2# Answer link Related questions What is long division of polynomials? How do I find a quotient using long division of polynomials? What are some examples of long division with polynomials? How do I divide polynomials by using long division? How do I use long division to simplify #(2x^3+4x^2-5)/(x+3)#? How do I use long division to simplify #(x^3-4x^2+2x+5)/(x-2)#? How do I use long division to simplify #(2x^3-4x+7x^2+7)/(x^2+2x-1)#? How do I use long division to simplify #(4x^3-2x^2-3)/(2x^2-1)#? How do I use long division to simplify #(3x^3+4x+11)/(x^2-3x+2)#? How do I use long division to simplify #(12x^3-11x^2+9x+18)/(4x+3)#? See all questions in Long Division of Polynomials Impact of this question 1514 views around the world You can reuse this answer Creative Commons License