How do you simplify and divide $(2 c^{3} - 3 c^{2} + 3 c - 4) \div (c - 2)$ $(2c^3-3c^2+3c-4)div(c-2)$ ?

Question

How do you simplify and divide $(2 c^{3} - 3 c^{2} + 3 c - 4) \div (c - 2)$ $(2c^3-3c^2+3c-4)div(c-2)$ ?

1 Answer

Impact of this question

2055 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-02T19:54:10

$2 c^{2} + c + 5 + \frac{6}{c - 2}$ $2c^2+c+5+6/(c-2)$

Explanation:

$one way is to use the divisor as a factor in the numerator$ $"one way is to use the divisor as a factor in the numerator"$

$consider the numerator$ $"consider the numerator"$

$2 c^{2} (c - 2) + 4 c^{2} - 3 c^{2} + 3 c - 4$ $color(red)(2c^2)(c-2)color(magenta)(+4c^2)-3c^2+3c-4$

$= 2 c^{2} (c - 2) + c (c - 2) + 2 c + 3 c - 4$ $=color(red)(2c^2)(c-2)color(red)(+c)(c-2)color(magenta)(+2c)+3c-4$

$= 2 c^{2} (c - 2) + c (c - 2) + 5 (c - 2) + 10 - 4$ $=color(red)(2c^2)(c-2)color(red)(+c)(c-2)color(red)(+5)(c-2)color(magenta)(+10)-4$

$= 2 c^{2} (c - 2) + c (c - 2) + 5 (c - 2) + 6$ $=color(red)(2c^2)(c-2)color(red)(+c)(c-2)color(red)(+5)(c-2)+6$

$quotient = 2 c^{2} + c + 5, remainder = 6$ $"quotient "=color(red)(2c^2+c+5)," remainder "=6$

$\Rightarrow \frac{2 c^{3} - 3 c^{2} + 3 c - 4}{c - 2} = 2 c^{2} + c + 5 + \frac{6}{c - 2}$ $rArr(2c^3-3c^2+3c-4)/(c-2)=2c^2+c+5+6/(c-2)$

Science

Math

Humanities

... and beyond

How do you simplify and divide $(2 c^{3} - 3 c^{2} + 3 c - 4) \div (c - 2)$ $(2c^3-3c^2+3c-4)div(c-2)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify and divide (2c3−3c2+3c−4)÷(c−2)(2c^3-3c^2+3c-4)div(c-2)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you simplify and divide $(2 c^{3} - 3 c^{2} + 3 c - 4) \div (c - 2)$ $(2c^3-3c^2+3c-4)div(c-2)$ ?