How do you simplify and divide $(2 y^{3} - 5 h^{2} + 22 h) \div (2 h + 3)$ $(2y^3-5h^2+22h)div(2h+3)$ ?

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How do you simplify and divide $(2 y^{3} - 5 h^{2} + 22 h) \div (2 h + 3)$ $(2y^3-5h^2+22h)div(2h+3)$ ?

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Answer 1 · 2017-04-16T09:52:26

$h^{2} - 4 h + 16 - \frac{48}{2 h + 3}$ $h^2-4h+16-48/(2h+3)$

Explanation:

One way is to use the divisor as a factor in the numerator.

$Consider the numerator$ $"Consider the numerator"$

$h^{2} (2 h + 3) - 3 h^{2} - 5 h^{2} + 22 h$ $color(red)(h^2)(2h+3)color(magenta)(-3h^2)-5h^2+22h$

$= h^{2} (2 h + 3) - 4 h (2 h + 3) + 12 h + 22 h$ $=color(red)(h^2)(2h+3)color(red)(-4h)(2h+3)color(magenta)(+12h)+22h$

$= h^{2} (2 h + 3) - 4 h (2 h + 3) + 16 (2 h + 3) - 48$ $=color(red)(h^2)(2h+3)color(red)(-4h)(2h+3)color(red)(+16)(2h+3)color(magenta)(-48$

$\Rightarrow quotient = h^{2} - 4 h + 16 and remainder = - 48$ $rArr"quotient "=color(red)(h^2-4h+16)" and remainder " =color(magenta)(-48)$

$\Rightarrow \frac{2 h^{3} - 5 h^{2} + 22 h}{2 h + 3} = h^{2} - 4 h + 16 - \frac{48}{2 h + 3}$ $rArr(2h^3-5h^2+22h)/(2h+3)=h^2-4h+16-48/(2h+3)$

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How do you simplify and divide $(2 y^{3} - 5 h^{2} + 22 h) \div (2 h + 3)$ $(2y^3-5h^2+22h)div(2h+3)$ ?

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Explanation:

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How do you simplify and divide (2y3−5h2+22h)÷(2h+3)(2y^3-5h^2+22h)div(2h+3)?

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How do you simplify and divide $(2 y^{3} - 5 h^{2} + 22 h) \div (2 h + 3)$ $(2y^3-5h^2+22h)div(2h+3)$ ?