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How do you simplify and divide $\frac{6 x y^{2} - 3 x y + 2 x^{2} y}{x y}$ $(6xy^2-3xy+2x^2y)/(xy)$ ?

1 Answer

Oct 12, 2016

We can factor out an $x y$ $xy$ in the numerator.

$= \frac{x y (6 y - 3 + 2 x)}{x y}$ $=(xy(6y - 3 + 2x))/(xy)$

$= 6 y + 2 x - 3, x y \neq 0$ $=6y + 2x - 3, xy !=0$

Hopefully this helps!

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