How do you simplify and divide $(9a^3b^2-18a^2b^3)/(3a^2b)$ ?

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Answer 1 · 2017-07-13T09:35:35

$3b(a-2b)$

$"factorise the numerator"$

$(9a^2b^2(a-2b))/(3a^2b)larr" cancel common factors"$

$=3b(a-2b)=3ab-6b^2$

How do you simplify and divide (9a^3b^2-18a^2b^3)/(3a^2b)(9a^3b^2-18a^2b^3)/(3a^2b)?