How do you simplify and divide $\frac{9 d^{3} + 5 d - 8}{3 d - 2}$ $(9d^3+5d-8)/(3d-2)$ ?

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How do you simplify and divide $\frac{9 d^{3} + 5 d - 8}{3 d - 2}$ $(9d^3+5d-8)/(3d-2)$ ?

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Answer 1 · 2017-02-04T16:42:03

$3 d^{2} + 2 d + 3$ $3d^2+2d+3$ with remainder $- 2$ $-2$

Explanation:

$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $3 d^{2} + 2 d + 3$ $3d^2+2d+3$
$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $- - - - -$ $-----$
$a a a a a 3 d - 2$ $color(white)(aaaaa)3d-2$ $∣$ $|$ $9 d^{3} + 5 d - 8$ $9d^3 +5d-8$
$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $9 d^{3} - 6 d^{2}$ $9d^3-6d^2$ $color(white)$
$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $- - - -$ $----$
$a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaa)$ $0 + 6 d^{2} + 5 d$ $0+6d^2+5d$
$a a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaaa)$ $6 d^{2} - 4 d$ $6d^2-4d$
$a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaa)$ $- - -$ $---$
$a a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaaa)$ $0 + 9 d - 8$ $0+9d-8$
$a a a a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaaaaa)$ $+ 9 d - 6$ $+9d-6$
$a a a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaaaa)$ $- - -$ $---$
$a a a a a a a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaaaaaaaa)$ $0 - 2$ $0-2$

The remainder is $= - 2$ $=-2$ and the quotient is $= 3 d^{2} + 2 d + 3$ $=3d^2+2d+3$

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How do you simplify and divide $\frac{9 d^{3} + 5 d - 8}{3 d - 2}$ $(9d^3+5d-8)/(3d-2)$ ?

1 Answer

Explanation:

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How do you simplify and divide (9d^3+5d-8)/(3d-2)9d3+5d−83d−2(9d^3+5d-8)/(3d-2)?

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How do you simplify and divide $\frac{9 d^{3} + 5 d - 8}{3 d - 2}$ $(9d^3+5d-8)/(3d-2)$ ?