How do you simplify and divide $(a^{3} b^{2} - a^{2} b + 2 a) {(- a b)}^{- 1}$ $(a^3b^2-a^2b+2a)(-ab)^-1$ ?

Question

How do you simplify and divide $(a^{3} b^{2} - a^{2} b + 2 a) {(- a b)}^{- 1}$ $(a^3b^2-a^2b+2a)(-ab)^-1$ ?

2 Answers

Impact of this question

4757 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-22T06:14:45

$- \frac{a^{2} b^{2} - a b + 2}{b}$ $-(a^2b^2-ab+2)/b$

Explanation:

Given -

$(a^{3} b^{2} - a^{2} b + 2 a) {(- a b)}^{- 1}$ $(a^3b^2-a^2b+2a)(-ab)^(-1)$

$\frac{a^{3} b^{2} - a^{2} b + 2 a}{- a b}$ $(a^3b^2-a^2b+2a)/(-ab)$

$\frac{a (a^{2} b^{2} - a b + 2)}{- a b}$ $(a(a^2b^2-ab+2))/(-ab)$

$- \frac{a^{2} b^{2} - a b + 2}{b}$ $-(a^2b^2-ab+2)/b$

Answer 2 · 2018-06-22T06:16:19

$- a^{2} b + a - \frac{2}{b}$ $-a^2b+a-2/b$

Explanation:

$\frac{a^{3} b^{2} - a^{2} b + 2 a}{- a b} = - \frac{a^{2} b}{a b} + \frac{a^{2} b}{a b} - \frac{2 \cdot a}{a b} =$ $(a^3b^2-a^2b+2a)/(-ab)=-(a^2b)/(ab)+(a^2b)/(ab)-(2*a)/(ab)=$
$- a^{2} b + a - \frac{2}{b}$ $-a^2b+a-2/b$

Science

Math

Humanities

... and beyond

How do you simplify and divide $(a^{3} b^{2} - a^{2} b + 2 a) {(- a b)}^{- 1}$ $(a^3b^2-a^2b+2a)(-ab)^-1$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify and divide (a3b2−a2b+2a)(−ab)−1(a^3b^2-a^2b+2a)(-ab)^-1?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you simplify and divide $(a^{3} b^{2} - a^{2} b + 2 a) {(- a b)}^{- 1}$ $(a^3b^2-a^2b+2a)(-ab)^-1$ ?