Question

How do you simplify and divide `(x^2-12x-45)div(x+3)`?

Answer 1

`(x-15), x!=-3`

Explanation:

`(x^2-12x−45)` is equal to `(x+3)(x-15)`, so the whole expression can be called:
`((x+3)(x-15))/(x+3)`
The `(x+3)` can be canceled from the top and bottom, leaving only `(x-15)`.
However, keep in mind that is `x` is negative 3, then the denominator will be 0, and you can't divide by zero. So it would be more accurate to say the simplified form is `(x-15), x!=-3`.