How do you simplify and divide $(x^{3} + y^{3}) \div (x + y)$ $(x^3+y^3)div(x+y)$ ?

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Answer 1 · 2016-12-12T06:11:38

The answer is $= x^{2} - x y + y^{2}$ $=x^2-xy+y^2$

We know that

$a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ $a^3+b^3=(a+b)(a^2-ab+b^2)$

So,

$(x^{3} + y^{3}) = (x + y) (x^{2} - x y + y^{2})$ $(x^3+y^3)=(x+y)(x^2-xy+y^2)$

Therefore,

$(x^3+y^3)/(x+y)=(cancel(x+y)(x^2-xy+y^2))/cancel(x+y)$

$=x^2-xy+y^2$

How do you simplify and divide (x^3+y^3)div(x+y)(x3+y3)÷(x+y)(x^3+y^3)div(x+y)?