How do you simplify and write $(4x^-4y^2)^-3$ with positive exponents?

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Answer 1 · 2018-07-10T00:16:17

$x^12/(64y^6)$

Our expression is the same as

$1/(4x^-4y^2)^3$

$4^3=color(blue)(64)$ , $(x^-4)^3=x^(-4*3)=color(blue)(x^(-12))$ , $(y^2)^3-y^(2*3)=color(blue)(y^6)$

With this in mind, we now have the following:

$1/(64x^-12y^6)$

We can make the negative exponent positive by bringing it to the numerator. We now have

$x^12/(64y^6)$

Hope this helps!

How do you simplify and write (4x^-4y^2)^-3(4x^-4y^2)^-3 with positive exponents?