How do you simplify #cos((3pi)/2-x)#?
1 Answer
Jan 11, 2018
Explanation:
#"using the "color(blue)"addition formulae for cosine"#
#•color(white)(x)cos(A+-B)=cosAcosB∓sinAsinB#
#rArrcos((3pi)/2-x)#
#=cos((3pi)/2)cosx+sin((3pi)/2)sinx#
#=0cosx+(-1)sinx#
#=-sinx#