How do you simplify ${(d^{2})}^{- 4}$ $(d^2)^-4$ ?

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How do you simplify ${(d^{2})}^{- 4}$ $(d^2)^-4$ ?

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Answer 1 · 2018-05-30T02:17:15

${(d^{2})}^{- 4} = \frac{1}{d^{8}}$ $(d^2)^(-4)=color(blue)(1/d^8$

Explanation:

Simplify:

${(d^{2})}^{- 4}$ $(d^2)^(-4)$

Apply the power rule of exponents: ${(a^{m})}^{m} = a^{m \cdot n}$ $(a^m)^m=a^(m*n)$

$d^{2 \cdot (- 4)}$ $d^(2*(-4))$

$d^{- 8}$ $d^(-8)$

Apply the negative exponent rule: $a^{- m} = \frac{1}{a^{m}}$ $a^(-m)=1/a^m$ .

$d^{- 8} = \frac{1}{d^{8}}$ $d^(-8)=1/d^8$

Answer 2 · 2018-05-30T02:18:28

$d^{- 8} or \frac{1}{d^{8}}$ $d^-8 or 1/d^8$

Explanation:

Because of the power of a power property, you'll want to multiply your exponents. 2 * -4 = -8, so this gives you $d^{- 8}$ $d^-8$ or, when simplified even further, $\frac{1}{d^{8}}$ $1/d^8$ .

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How do you simplify ${(d^{2})}^{- 4}$ $(d^2)^-4$ ?

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