How do you simplify #f(theta)=2tan2theta-3sin2theta+sec2theta# to trigonometric functions of a unit #theta#? Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer Shwetank Mauria May 2, 2016 #f(theta)=(4tantheta)/(1-tan^2theta)-6sinthetacostheta+1/(2cos^2theta-1)# Explanation: #f(theta)=2tan2theta-3sin2theta+sectheta# or #f(theta)=2xx(2tantheta)/(1-tan^2theta)-3xx2sinthetacostheta+1/(cos2theta)# or #f(theta)=(4tantheta)/(1-tan^2theta)-6sinthetacostheta+1/(2cos^2theta-1)# Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for #sin 2x = cos x# for the interval #[0,2pi]#? How do you find all solutions for #4sinthetacostheta=sqrt(3)# for the interval #[0,2pi]#? How do you simplify #cosx(2sinx + cosx)-sin^2x#? If #tan x = 0.3#, then how do you find tan 2x? If #sin x= 5/3#, what is the sin 2x equal to? How do you prove #cos2A = 2cos^2 A - 1#? See all questions in Double Angle Identities Impact of this question 1340 views around the world You can reuse this answer Creative Commons License