How do you simplify #i^40+5-6i#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer Cosmic Defect Feb 28, 2016 #i^{40}+5-6i=(i^2)^20+5-6i# #\qquad \qquad \qquad \qquad \qquad =(-1)^20+5-6i=6-6i=6(1-i)# Explanation: Straight forward - no explanation needed Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1368 views around the world You can reuse this answer Creative Commons License