Question

How do you simplify `ln(1/2) - ln(1)`?

Answer 1

`-ln2`

Explanation:

From laws of logs, `ln(a/b)=lna-lnb`

and `ln(1)=0` since `e^0=1`.

Therefore `ln(1/2)-ln(1)=(ln1-ln2)-ln1`

`=0-ln2-0`

`=-ln2`