How do you simplify #ln(3x^2-9x)+ln(1/(3x))#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer A. S. Adikesavan May 3, 2016 #log (x-3)#, x > 3. Explanation: Use log #abc = log a + log b + log c and log(1/d) = - log d#, #log (3x^2-9x)+log(1/(3x))# #=log((3)(x)(x-3))-log( (3)(x))# #=log 3+log x + log(x-3)-log 3 - log x# #=log (x-3)#, with x > 3.. Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 4049 views around the world You can reuse this answer Creative Commons License