How do you simplify ${ln e}^{2}$ $ln e^2$ ?

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Answer 1 · 2018-04-27T04:29:34

2

$ln (x)$ $ln(x)$ is asking $e$ $e$ to the power of what is $x$ $x$

In this case, $e$ $e$ to the power of $2$ $2$ is $e^{2}$ $e^2$

thus, $ln (e^{2}) = 2$ $ln(e^2)=2$

Another way is using the property of logarithms that says $ln (a^{b}) = b \cdot ln (a)$ $ln(a^b)=b*ln(a)$

In this case, $a = e$ $a=e$ and $b = 2$ $b=2$
Thus, $ln (e^{2}) = 2 \cdot ln (e) = 2 \cdot 1 = 2$ $ln(e^2)=2*ln(e)=2*1=2$

How do you simplify lne2ln e^2?