Question

How do you simplify `log5(x + 4) -log5(x + 1)`?

Answer 1

I got as far as: `log[(x+4)/(x+1)]`

Explanation:

I would use the fact that:
`logx-logy=log(x/y)` to get:
`log5(x+4)-log5(x+1)=log[(cancel(5)(x+4))/(cancel(5)(x+1))]=log[(x+4)/(x+1)]`