How do you simplify $sin ({cos}^{- 1} (\frac{3}{5}))$ $Sin( cos^-1 (3/5))$ ?

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Answer 1 · 2016-10-31T19:29:21

$sin ({cos}^{- 1} (\frac{3}{5})) = \frac{4}{5}$ $sin(cos^-1(3/5)) = 4/5$

$sin ({cos}^{- 1} (\frac{3}{5})) = \sqrt{1 - {cos}^{2} ({cos}^{- 1} (\frac{3}{5}))}$ $sin(cos^-1(3/5)) = sqrt(1 - cos^2(cos^-1(3/5))$

$sin ({cos}^{- 1} (\frac{3}{5})) = \sqrt{1 - {(cos ({cos}^{- 1} (\frac{3}{5})))}^{2}}$ $sin(cos^-1(3/5)) = sqrt(1 - (cos(cos^-1(3/5)))^2$

$sin ({cos}^{- 1} (\frac{3}{5})) = \sqrt{1 - {(\frac{3}{5})}^{2}}$ $sin(cos^-1(3/5)) = sqrt(1 - (3/5)^2)$

$sin ({cos}^{- 1} (\frac{3}{5})) = \sqrt{1 - \frac{9}{25}}$ $sin(cos^-1(3/5)) = sqrt(1 - 9/25)$

$sin ({cos}^{- 1} (\frac{3}{5})) = \sqrt{\frac{16}{25}}$ $sin(cos^-1(3/5)) = sqrt(16/25)$

$sin ({cos}^{- 1} (\frac{3}{5})) = \frac{4}{5}$ $sin(cos^-1(3/5)) = 4/5$

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