Question

How do you simplify `sin(tan^-1(4x))`?

Answer 1

`(4x)/sqrt(16x^2+1)`

Explanation:

Let `a = tan^(-1) (4x)` in Q1 or Q4., wherein, like tangent, sine is

positive ( when x > 0) or 0 or negative

The given expression is `sin a = (4x)/sqrt(16x^2+1)`.