How do you simplify $sin(tan^-1(4x))$ ?

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Answer 1 · 2016-08-09T07:49:25

$(4x)/sqrt(16x^2+1)$

Let $a = tan^(-1) (4x)$ in Q1 or Q4., wherein, like tangent, sine is

positive ( when x > 0) or 0 or negative

The given expression is $sin a = (4x)/sqrt(16x^2+1)$ .

How do you simplify sin(tan^-1(4x))sin(tan^-1(4x))?