How do you simplify $sqrt(3/(27y^6))$ ?

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Answer 1 · 2015-09-25T01:52:53

$color(red)(sqrt(3/(27y^6))= 1/(3y^3))$

First divide the numerator and denominator by $3$ .

$sqrt(3/(27y^6)) = sqrt(1/(9y^6))$

Remember that $sqrt(x^n) = x^(n/2)$

So $sqrt(y^6) = y^(6/2) = y^3$ and

$sqrt(1/(9y^6)) = 1/(3y^3)$

∴ $sqrt(3/(27y^6))= 1/(3y^3)$

How do you simplify sqrt(3/(27y^6))sqrt(3/(27y^6))?