How do you simplify #sqrt(63w^36)#?

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Answer 1 · 2017-07-15T14:40:58

#3sqrt(7)*w^18=3w^18sqrt(7)#

#sqrt(63w^36)=sqrt(63)*sqrt(w^36)#

#sqrt(w^36)=(w^36)^(1/2)=w^(36/2)=w^18#

#sqrt(63)=sqrt(a*b)#, where a nd b are factors of 63, and one is a perfect square number.

Two factors of 63 are 9 and 7.

#sqrt(63)=sqrt(9*7)=sqrt(9)*sqrt(7)=3sqrt(7)#.

As #sqrt(63w^36)=sqrt(63)*sqrt(w^36)#, and we calculated thise vakues, it is just #3w^18sqrt(7)#