How do you simplify #sqrt(64/81)#?

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Answer 1 · 2016-06-05T09:12:09

#= 8/9#

For multiplication and division involving roots, you can find the roots separately.

So #sqrt(64/81) = sqrt64/sqrt81#

#= 8/9#

However for addition and subtraction you have to work with the terms as they are given

#sqrt(16 + 9) " is not the same as " sqrt16 +sqrt9#

#= sqrt25 " "= 4 + 3#

#= 5 " "= 7#