How do you simplify #(sqrt10 - sqrt 5) /( sqrt 10 + sqrt 5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Deepak G. Aug 11, 2016 #=3-2sqrt2# Explanation: #(sqrt10-sqrt5)/(sqrt10+sqrt5)# Multiplying both the sides by #sqrt(10)-sqrt(5)# We get #(sqrt10-sqrt5)^2/((sqrt10+sqrt5)(sqrt10-sqrt5))# #=(10+5-2timessqrt10timessqrt5)/(10-5)# #=(15-10sqrt2)/5# #=5(3-2sqrt2)/5# #=3-2sqrt2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 6122 views around the world You can reuse this answer Creative Commons License