How do you simplify #sqrt3(sqrt12+sqrt6)#?

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Answer 1 · 2016-10-24T15:57:48

#=6+3sqrt2#

Firstly multiply the brackets.

#sqrt3(sqrt12+sqrt6)=sqrt3sqrt12+sqrt3sqrt6#

#=sqrt36+sqrt18#

Now simplify the square roots.

#=6+sqrt(9xx2)=6+sqrt9sqrt2#

#=6+3sqrt2#