How do you simplify $\sqrt{675} - \sqrt{27}$ $sqrt675-sqrt27$ ?

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How do you simplify $\sqrt{675} - \sqrt{27}$ $sqrt675-sqrt27$ ?

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Answer 1 · 2018-03-12T04:57:24

$12 \sqrt{3}$ $12sqrt3$

Explanation:

$\sqrt{675} = \sqrt{225 \times 3} = 15 \sqrt{3}$ $sqrt675=sqrt{225\times3}=15sqrt3$
$\sqrt{27} = \sqrt{9 \times 3} = 3 \sqrt{3}$ $sqrt27=sqrt{9\times3}=3sqrt3$
$\sqrt{675} - \sqrt{27} = 15 \sqrt{3} - 3 \sqrt{3} = 12 \sqrt{3}$ $sqrt675-sqrt27=15sqrt3-3sqrt3=12sqrt3$

Answer 2 · 2018-03-12T06:14:46

$\sqrt{675} - \sqrt{27} = 12 \sqrt{3}$ $sqrt(675)-sqrt(27)=color(blue)(12sqrt3$

Explanation:

Simplify:

$\sqrt{675} - \sqrt{27}$ $sqrt(675)-sqrt(27)$

Prime factorize each radicand.

$\sqrt{3 \cdot 3^{2} \cdot 5^{2}} - \sqrt{3^{2} \cdot 3}$ $sqrt(3*3^2*5^2)-sqrt(3^2*3)$

Apply the rule: $\sqrt{a^{2}} = a$ $sqrt(a^2)=a$

$3 \cdot 5 \sqrt{3} - 3 \sqrt{3}$ $3*5sqrt3-3sqrt3$

Simplify.

$15 \sqrt{3} - 3 \sqrt{3}$ $15sqrt3-3sqrt3$

Numbers that have the same square root can be added or subtracted.

$15 \sqrt{3} - 3 \sqrt{3} =$ $15sqrt3-3sqrt3=$

$12 \sqrt{3}$ $12sqrt3$

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How do you simplify $\sqrt{675} - \sqrt{27}$ $sqrt675-sqrt27$ ?

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How do you simplify sqrt675-sqrt27√675−√27sqrt675-sqrt27?

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How do you simplify $\sqrt{675} - \sqrt{27}$ $sqrt675-sqrt27$ ?