How do you simplify $tan (x + π)$ $tan(x+pi)$ ?

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How do you simplify $tan (x + π)$ $tan(x+pi)$ ?

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Answer 1 · 2018-03-30T01:09:59

This simplifies to $tan x$ $tanx$

Explanation:

We use the addition formula for tangent, $tan (A + B) = \frac{tan A + tan B}{1 - tan A tan B}$ $tan(A + B) = (tanA + tanB)/(1 - tanAtanB)$ , and the fact that $tan (π) = \frac{0}{1} = 0$ $tan(pi) = 0/1 = 0$ .

Therefore:

$tan (x + π) = \frac{tan x + tan (π)}{1 - tan x tan (π)} = \frac{tan x + 0}{1 - 0} = tan x$ $tan(x + pi) = (tanx + tan(pi))/(1 - tanxtan(pi)) = (tanx + 0)/(1 - 0) = tanx$

Hopefully this helps!

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How do you simplify $tan (x + π)$ $tan(x+pi)$ ?

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How do you simplify tan(x+π)tan(x+pi)?

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Explanation:

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Impact of this question

How do you simplify $tan (x + π)$ $tan(x+pi)$ ?